Last Activity: 11 Years ago
.5
its bond order is o.5
0.5
in molecular orbital theory bond order =1/2 (electron in b.m.o. - electron in ab.m.o)
The bond order formed by LI 2 is BO = ½ (4 – 2) = 1 Li–Li single bond. A molecul...
bond order =1/2(Nb-Na) where Nb= number of bonding orbitals=4
Na=number of non bonding orbitals=2
B.O=0.5
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No. of bonding elecrtons =3 (valence), anti bonding =0 (given its state)
thus =bond order =3/2=1.2
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