Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

why bond angles of the chalcogens go on decreasing down the group? the charge density decreases and so the angle should increase as initially lp-lp repulsion was dominant but later bp-bp repulsion takes the lead...

why bond angles of the chalcogens go on decreasing down the group?  the charge density decreases and so the angle should increase  as initially lp-lp repulsion was dominant but later bp-bp repulsion takes the lead...

Grade:12th Pass

1 Answers

ruchi yadav
askIITians Faculty 27 Points
7 years ago
All the members form volatile hydrides of the type AH3. All hydrides are pyramidal in shape. The bond angle decreases on moving down the group due to decrease in bond pair–bond pair repulsion.

NH3 PH3 AsH3 SbH3 BiH3
107O 94O 92O 91O 90O
The decreasing order of basic strength of hydrides is as follows :
NH3> PH3AsH3> SbH3> BiH3.
The increasing order of boiling points is as follows :
PH3< AsH3< NH3< SbH3.
NH3is thermally most stable andBiH3is least stable. This is because inNH3, N – H covalent bond is the strongest due to small size of N atom. Hence, the decomposition temperature ofNH3will be the highest.The increasing order of reducing character is as follows,NH3< PH3AsH3< SbH3< BiH3.

Thank You
Ruchi
Askiitians faculty

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free