[Ni9(CO4)]possesses tetrahydralgeometry while [Ni( CN)4]2-is asquare planer explain why?

[Ni(CN)4]2- is square planar because CN is strong ligand it in the presence of this ligand electrons are pair up in 3d orbitals.so inner orbital comples it is undergo dsp2 hybridization so it is in square panar geometry while [Ni(co)4] it is undergo sp3 hybridization so it has tetrahydral geometry .

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[Ni(CN)4]2- is square planar because CN is strong ligand it in the presence of this ligand electrons are pair up in 3d orbitals.so inner orbital comples it is undergo dsp2 hybridization so it is in square panar geometry while [Ni(co)4] it is undergo sp3 hybridization so it has tetrahydral geometry .