Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

[Ni9(CO4)]possesses tetrahydral geometry while [Ni( CN)4]2- is asquare planer explain why?

[Ni9(CO4)]possesses tetrahydral geometry while [Ni( CN)4]2- is asquare planer explain why?

Grade:12

2 Answers

Srikanth Neeli
38 Points
9 years ago

[Ni(CN)4]2- is square planar because CN is strong ligand it in the presence of this ligand electrons are pair up in 3d orbitals.so inner orbital comples it is undergo dsp2 hybridization so it is in square panar geometry while [Ni(co)4] it is undergo sp3 hybridization so it has tetrahydral geometry .

 

if you satisfy my answer please click on yes

upender surepally
126 Points
9 years ago

[Ni(CN)4]2- is square planar because CN is strong ligand it in the presence of this ligand electrons are pair up in 3d orbitals.so inner orbital comples it is undergo dsp2 hybridization so it is in square panar geometry while [Ni(co)4] it is undergo sp3 hybridization so it has tetrahydral geometry .

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free