the formula is sqrt(n(n+2) here the ''n'' is the number of unpaired electrons present in a metal.here Fe has ooxidation state +3 and it has 5 unpaired electrons...so we can take n=5
therefore the answer will be 5.91 B.M
Last Activity: 13 Years ago
mannam kiran kumar
hai my dear pithre the magnetic momentum of K3[FeF6] is 5.9B ok,,,,,
Last Activity: 13 Years ago
Theresh Babu Benguluri
Dear Prasanth
IN THE COMPLEX K3[FeF6] the metal element is Ferrous .... So the oxidation state of the Ferrous is +3 ..
I THINK U KNOW THAT Fe+3 have 5 unpaired d-electrons So the magnetic moment of K3[FeF6}
========================= (35)0.5 ===> 5.91 bm
Approved
Last Activity: 13 Years ago
swagatam
see , fe is in + 3 oxidation state, therfore there will be three unpaired electrones in d orbital , so magnetic moment will be 3.87
Last Activity: 7 Years ago
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