the formula is sqrt(n(n+2) here the ''n'' is the number of unpaired electrons present in a metal.here Fe has ooxidation state +3 and it has 5 unpaired electrons...so we can take n=5
therefore the answer will be 5.91 B.M
mannam kiran kumar
Last Activity: 13 Years ago
hai my dear pithre the magnetic momentum of K3[FeF6] is 5.9B ok,,,,,
Theresh Babu Benguluri
Last Activity: 13 Years ago
Dear Prasanth
IN THE COMPLEX K3[FeF6] the metal element is Ferrous .... So the oxidation state of the Ferrous is +3 ..
I THINK U KNOW THAT Fe+3 have 5 unpaired d-electrons So the magnetic moment of K3[FeF6}