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Grade: 12
        

find the energy that must be transferrred as heat to evaporate 1 kg of water at 25 degree celsius.answer is 2440 kJ.how come?please solve this

7 years ago

Answers : (4)

AAYUSH KESHAVA
22 Points
							

ΔQ=msΔT;      m=1kg; ΔT=100-25=75°C; s=specific heat for water=4184 J/kg/°C

So, ΔQ=1* 4184 *75=313800J              -----  Answer

7 years ago
ankitesh gupta
63 Points
							

ACTUALLY THE ANSWER THAT YOU HAVE GIVEN IS WRONG 

   IF THE WATER WANT TO FULLY EVAPORATE FIRST IT WILL MAKE ITS TEMPRATURE TO 100 DEGREE CELICIUS THEN IT WILL CHANGE ITS STATE TO GASEOUS FORM BY PHASE TRANSFORMATION SO TOTAL HEAT REQUIRED

    ms(T2-T1) +  mL 

   where ''m'' is the mass and ''s'' is heat capacity of water ''L'' is latent heat of vapourisation ''T1'' is intial temprature and ''T2'' is final temprature

  S = 4200J/KG/DEGREE CELCIUS

  L  = 2.26 X 106 J/KG/DEGREE CELCIUS 

  T1 = 25 DEGREE CELCIUS

  T2  = 100 DEGREE CELCIUS

SUBSTITUTE THE VALUES IN THE EQUATION AND GET YOUR ANSWER  WHICH COMES OUT TO BE 2575KJ

 

 

  IF YOU ARE SATISFIED PLZZ APPROVE MY ANSWER


7 years ago
SHIVAM JAIN
18 Points
							

answer was not correct it was 2440kJ according to solution manual.

7 years ago
SHIVAM JAIN
18 Points
							

any way looks to be correct and close to the answer

7 years ago
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