MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        Submit your detailed Question here...29.2 % (w/w) HCl stock solution has density of 1.25 g mL-1. The molecular weight of HCl is 36.5 g mol-1.

The volume (mL) of stock solution required to prepare a 200 mL solution of 0.4 M HCl is
7 years ago

Answers : (2)

Sunil Kumar FP
askIITians Faculty
183 Points
							29.2 % (w/w) HCl stock solution has density of 1.25 g mL-1. The molecular weight of HCl is 36.5 g mol-1. The volume (mL) of stock solution required to prepare a 200 mL solution of 0.4 M HCl is as follows
stock solution of HCl=29.2%(w/w)
molarity of stock solution of HCl=29.2*1000*1.25/36.5*100
if volume of stock solution required is Vml
then
v*29.2/36.5*1000/80=200*.4
v=8ml
5 years ago
Urvi
13 Points
							
M1= 29.2*1.25*10/36 .5
M1=10 
M2=0.4
V2=200
M1V1=M2V2
10*V1=0.4*200
V1=0.4*200/10
V1=8
So the answer is 8 ml 
And this is solved by the formula 
Molarity=%(w/w) *density of solution*10/molar mass of solute 
 
 
 
8 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 54 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details