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the position and momentum of 1 kev electron are simultaneously determined.if its position is located to within 1Angstorm, what is the percentage uncertainity in its momentum?
Dear Prince,
Solve the problem using equations:
KE = 1/2 mv^2Δp=h/ΔxΔp/p .
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Cracking IIT just got more exciting,It s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and win by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple to download the toolbar….
So start the brain storming…. become a leader with Elite Expert League ASKIITIANS
Thanks
Aman Bansal
Askiitian Expert
tnx sir,
but i am not being able to solve it.
it will be vry kind if you solve it by puttng values!
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