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Inorganic Chemistry

Number of gm of oxygen in 32.2 g Na2SO4.10H2O is

Profile image of Sandeep Lakha
14 Years agoGrade
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3 Answers

Profile image of pankaj kumar raman
14 Years ago

wt. of Na2SO4.10H2O=46+32+14*16+20=322gm

the above compound contain 14 gm Oxygen atom

hence 32.2 gm compound will contain 1.4 gm Oxygen atom

Profile image of eaishwary bajpai
14 Years ago

molecular mass of Na2SO4.10H2O =322 gm

322gm has 224 gm Oxgen 

 32.2 gm will have 22.4 gm oxygen


Profile image of Rupsa Ghosh
8 Years ago
No. of oxygen atoms in one molecule =4+10=14Thus moles of oxygen in n moles of compound=n*14Molar mass of Na2SO4.10H2O=46+32+64+180=322g/molThus 32.2g=32.2/322=0.1 mols Thus moles of O=0.1*14=1.4So weight is 16*1.4=22.4g