Inorganic Chemistry
a gas has vapour density 11.2 the volume occupied by 1g of gas at NTP is a) 1L b) B)11.2L c)22.4L D)4L
a gas has vapour density 11.2 the volume occupied by 1g of gas at NTP is a) 1L b) B)11.2L c)22.4L D)4L
4 Answers
Yogita Nain
molecular mass of gas = 2*V.D.
=2*11.2 =22.4
no of moles of gas = weight/ molecular mass
= 1/22.4
vol oF gas = no of moles * V
= 1/ 22.4 * 22.4
= 1 L
Godfrey Classic Prince
Dear princess payal,
The answer is a) 1L ..
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aravind
its A
SINCE VAPOUR DENSITY OF A GAS * 2 =MOLECULAR WEIGHT OF THA GAS
M.WT.=2*V.D
= 2*11.2
= 22.4g
therefore 22.4g 0f gas at ntp occupies 22.4 L volume
then 1g oggas at ntp occupies 1L
ghg
The answer to your question is 1 litre.
This is because VD=2*Molecular mass
SINCE VAPOUR DENSITY OF A GAS * 2 =MOLECULAR WEIGHT OF THA GAS
M.WT.=2*V.D
= 2*11.2
= 22.4g
therefore 22.4g 0f gas at ntp occupies 22.4 L volume
then 1g oggas at ntp occupies 1L
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