0

Guest

Courses New

a gas has vapour density 11.2 the volume occupied by 1g of gas at NTP is a) 1L b) B)11.2L c)22.4L D)4L

a gas has vapour density 11.2 the volume occupied by  1g of gas at NTP is a) 1L b) B)11.2L c)22.4L D)4L

Grade:

4 Answers

Yogita Nain
5 Points
10 years ago

molecular mass of gas = 2*V.D.

                                 =2*11.2 =22.4

no of moles of gas = weight/ molecular mass

                            = 1/22.4

vol oF gas = no of moles * V

                = 1/ 22.4 * 22.4

                = 1 L

Godfrey Classic Prince
633 Points
10 years ago

Dear princess payal,

The answer is a) 1L ..

 

All the Very Best & Good Luck to you..

Hope this helped you immensely..

 

Regards,

AskIITians Expert,

Godfrey Classic Prince

IIT-M

 

Please approve my answer if you liked it by clicking on "Yes" given below..!!Smile

aravind
23 Points
7 years ago
its A 
SINCE VAPOUR DENSITY OF A GAS  * 2 =MOLECULAR WEIGHT OF THA GAS 
M.WT.=2*V.D 
          = 2*11.2
          = 22.4g
therefore 22.4g 0f gas at ntp occupies 22.4 L volume 
then 1g oggas at ntp occupies 1L 
 
ghg
11 Points
5 years ago
The answer to your question is 1 litre.
This is because VD=2*Molecular mass
 
SINCE VAPOUR DENSITY OF A GAS  * 2 =MOLECULAR WEIGHT OF THA GAS 
M.WT.=2*V.D 
          = 2*11.2
          = 22.4g
therefore 22.4g 0f gas at ntp occupies 22.4 L volume 
then 1g oggas at ntp occupies 1L 
 

Think You Can Provide A Better Answer ?

Other Related Questions on Inorganic Chemistry

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More