Why in brown ring complex NO converts Fe(II) into Fe(I) whereas in K3[Fe(CN)5NO] it does not?

Dear Debajyoti,

A common nitrate test, known as the brown ring test can be performed by adding iron(II) sulfate to a solution of a nitrate, then slowly adding concentrated sulfuric acid such that the sulfuric acid forms a layer below the aqueous solution. A brown ring will form at the junction of the two layers, indicating the presence of the nitrate ion. Note that the presence of nitrite ions will interfere with this test.The overall reaction is the reduction of the nitrate ion by iron(II) which is oxidized to iron(III) and formation of a nitrosyl complex.

NO₃^- + 3Fe²⁺ + 4H⁺ → 3Fe³⁺ + NO + 2H₂O

[Fe(H₂O)₆]²⁺ + NO → [Fe(H₂O)₅(NO)]²⁺ + H₂O

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Dear Debajyoti,

Please dont post same query again and again..

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A common nitrate test, known as thebrown ring testcan be performed by addingiron(II) sulfateto a solution of a nitrate, then slowly adding concentratedsulfuric acidsuch that the sulfuric acid forms a layer below the aqueous solution. A brown ring will form at the junction of the two layers, indicating the presence of the nitrate ion.Note that the presence of nitrite ions will interfere with this test.The overall reaction is thereductionof the nitrate ion by iron(II) which is oxidized to iron(III) and formation of a nitrosyl complex.

NO3-+ 3Fe2++ 4H+? 3Fe3++ NO + 2H2O
[Fe(H2O)6]2++ NO ? [Fe(H2O)5(NO)]2++ H2O


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Ruchi
Askiitians Faculty