Inorganic Chemistry> Classification of elements priodicity...

if there were ten periods in the periodic table then how many elements would this period can maximum comprise of ?

give answer with explanation

ankit agrawal , 13 Years ago

Grade 11

7 Answers

Emaad Mulla

all elements hav orbits and orbits can hav 4 types of orbitals..

s p d f

each orbital has its own capacity for electrons..

s=2

p=6

d=10

f=14

max no of elements in a period = max no of electrons in its outer most shell

since period no increases, the no of orbitals in the outermost orbit increase.

so max electons inc and so capacity of each period increases.

Eg: 1st orbit has only s orbital so only 2 ELEMENTS in the 1st period

2nd orbit has s and p orbitals so 8 electrons.. so 8 elements in 2nd period..

so on...

since an orbit can hav only s p d f orbitals 10th period will hav 2+6+10+14 elements

Last Activity: 13 Years ago

abhishek agarwal

the correct ans is 72... but even i dn''t kw the explanation......

Last Activity: 12 Years ago

Salil

#Method 1
n*s n-4*h n-3*g n-2*f n-1*d n*p
Put value of n. If orbital exists then count 2e- per orbital (2h or 3g do not exist). Sum up the electrons. Gives the no. of elements in a period.
#Method 2
Period no even. 2*(n+2/2)^2
Period no odd. 2*9n+1/2)^2
Here n = 10
Putting directly in formula.
Elements = 72

Last Activity: 9 Years ago

Benja

Trick to find no. of elements in a period.For odd periods: (1st, 3rd, 5th....periods)(n+1)^2/2 For even periods (2nd, 4th, 6th....periods)So coming to the question, no. Of elements present in 10th period will be-(n+2)^2/2{USING THIS FORMULA SINCE 10th PERIOD IS EVEN)= (10+2)^2/2=(12)^2/2=144/2=72 elements will be present in the 10th period.

Last Activity: 8 Years ago

Tejus

sir is not with s p d f also there will be g and others which would lead to the correct answer

I would have done it but don't known to me no. of electrons in g and h orbital plz notify whether I am on correct way to answer or not.

Last Activity: 8 Years ago

Harsh

Following afbau's principle

Energy shells are filled according to their energy order

i.e.

In the diagonal relation manner like the following

5s 5p 5d 5f 5g

4s 4p 4d 4f

3s 3p 3d

2s 2p

Where electrons start from 1s (first shell) then 2s 2p (second shell), 3s 3p (3rd shell) 4s 3d 4p (4th shell) and so on..

So for the 10th shell..it ll be

10s 6h 5g 4f 9d 10p

And so adding the no. Of electeons

Total electrons =total no. Of elements in that period

= 2+22+18+14+10+6=72

Last Activity: 7 Years ago

ankit singh

The maximum number of elements in a period is equal to the maximum number of electrons in its outer most shell. As we move from one period to the other the number of electrons it can accommodate in its orbital increases (in the order of s, p, d and f).

But the maximum number of electrons a period can accommodate is = 2 + 6 + 10 + 14 = 32

So, we would have 32 elements in the 10^th period.

Last Activity: 5 Years ago