# if there were ten periods in the periodic table then how many elements would this period can maximum comprise of ? give answer with explanation

if there were ten periods in the periodic table then how many elements would this period can maximum comprise of ?

give answer with explanation

## 7 Answers

s p d f

each orbital has its own capacity for electrons..

s=2

p=6

d=10

f=14

max no of elements in a period = max no of electrons in its outer most shell

since period no increases, the no of orbitals in the outermost orbit increase.

so max electons inc and so capacity of each period increases.

Eg: 1st orbit has only s orbital so only 2 ELEMENTS in the 1st period

2nd orbit has s and p orbitals so 8 electrons.. so 8 elements in 2nd period..

so on...

since an orbit can hav only s p d f orbitals 10th period will hav 2+6+10+14 elements

the correct ans is 72... but even i dn''t kw the explanation......

n*s n-4*h n-3*g n-2*f n-1*d n*p

Put value of n. If orbital exists then count 2e- per orbital (2h or 3g do not exist). Sum up the electrons. Gives the no. of elements in a period.

#Method 2

Period no even. 2*(n+2/2)^2

Period no odd. 2*9n+1/2)^2

Here n = 10

Putting directly in formula.

Elements = 72

But the maximum number of electrons a period can accommodate is = 2 + 6 + 10 + 14 = 32

So, we would have 32 elements in the 10

^{th}period.