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If 1.47 A of current was passed through an aqueous solution of a metal salt for 525 seconds and 863 mg of metal was deposited, then what was the charge on metal ion? how would you work this out? thanks.:)
If 1.47 A of current was passed through an aqueous solution of a metal salt for 525 seconds and 863 mg of metal was deposited, then what was the charge on metal ion?
how would you work this out?
thanks.:)
Using Farady's First Law of Electrolysis.m = ZItorz = m/It = 863000/ (1.47)(525) =1118.16Charge on metal ion = 1118.16 x1.60217657 × 10-19coulombsThanks & RegardsPankaj SinghaskIITians Faculty
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