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# Certain non-metal X forms two oxides I and II . The mass percentage of oxygen in I(X4 O6) is 43.7% which is the same  as that of X in the 2nd oxide.Find the formula of 2nd oxide. (Based on law of multiple proportions...... pls xplain each step carefully)

Chetan Mandayam Nayakar
312 Points
9 years ago

Dear Ajay,

let 'm' be atomic mass of X. let formula of second oxide be XuOv

mass %age of oxygen in I=96/(96+4m)=24/(m+24)=0.437,m+24=24/0.437,m=31(approx.)

31u/(31u +16v)=0.437,31u/0.437=31u+16v

31/0.437=31+16(v/u)

v/u=2.5,therefore II is X2O5

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