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A metal complex having composition Cr(NH3)4 Cl2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white ppt.readily soluble in dilute aq.ammonia,whereas B gives a pale yellow ppt.soluble in concentrated ammonia.Write the formula of A and B and state hybridisation of chromium in each.Calculate their magnetic moments .
Dear Ankit ,
Formula of A is [Cr(NH3)4ClBr]Cl + AgNO3 ?? AgCl? (white)
Formula of B is [Cr(NH3)4Cl2]Br + AgNO3 ?? AgBr? (yellow)
Cr is in +3 oxidation state i.e. 3d3 system.
Therefore the hybridisation of Cr is d2sp3
and spin only magnetic moment.= 3.87 BM
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