details of hybridisation of MnO4-

Dear Najam Uddin,

I = GA + 1/2(VE -V -C)

= 4 + 1/2(7 -4+1)

= 6

hybridisation = sp³d²

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HYBRIDISATION  DEPICTING FORMULA IS
HYBRIDISATION=1/2{VALENCE ELECTRONS OF CENTRAL ATOM +TOTAL MONOVALENTLY BOND ATOMS-ANION CHARGE +CATION CHARGE}
THEREFORE FOR MnO4- H=1/2{7+0+1} = 4 {SP3}

MnO4- has d3s hybridization. Here, Mn is in +7 OS. The oxygen atoms act as ligands to the manganese center, and donate electrons to its 3 dxy, dyz and dzy orbitals and to 4s orbital, thus the hybridization is d3s. Feel free to ask more.

I think its d2sp hybridization.because this MnO4- has tetrahedral geometry and it has no lone pairs.only 3 double bond and a single bond.that means 4 sigma bonds and 3 pye bonds.so therefore 7 unpaired electrons should be there in the orbitals.in the excitaion one of two electrons of 4s is excited to the 4p orbital.then it gives 7 valance electrons to form bonds with 4 Oxygens.so we can get as hybrid orbitals 2 3d orbitals,4s orbital and 1 4p orbital for the hybridization.this is an idea got to think..if it is incorrect please let me know.thank you.