1.CALCULATE THE NO OF WAVES MADE BY ELECTRON IN 5TH BOHR ORBIT OF H ATOM2.A HYDROGEN LIKE SYSTEM HAS IONIZATION ENERGY 11808 KJ/MOL.FIND NO OF PROTONS IN NUCLEUS OF ATOM

mvr=5h/2pi,pr=5h/2pi, p=5h/2pir,lambda= h/p=2pir/5 thus number of waves made by electron=5, let z be number of protons,

ionization energy =13.6*1.6*(10^-19)*6.02*(10^23)*z²=11808000, solve for z

Dear student,

No. of waves=n(n-1)/2

BEST OF LUCK..!!!!


 

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