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if an element shows two oxidation states +2 and +3 and form oxide in such a way that ratio of the element showing +2 and +3 state is 1:3 in compound. formula of compound is....????
(please tell me how to solve it)
1*X0+3*X2O3, X3O4
let no of atoms in +2 is x
so, no of atoms in +3 is 3x
hence, charge on atom A is 2x +3[3x] = 11x
SO, NET CHARGE ON OXYGEN IS 11x
let no of oxygen atoms be y
charge on one oxygen atom is 2
2y = 11x
so, y=11x/2
hence compound is AxA3x[O11X/2]
i.e A4x[O11x/2]
i.eA8x[O11x]
i.eA8O11
it's wrong....
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