if an element shows two oxidation states +2 and +3 and form oxide in such a way that ratio of the element showing +2 and +3 state is 1:3 in compound. formula of compound is....????

(please tell me how to solve it)

1*X0+3*X₂O₃, X3O4

let no of atoms in +2 is x

so, no of atoms in +3 is 3x

hence, charge on atom A is  2x +3[3x] = 11x

SO, NET CHARGE ON OXYGEN IS 11x

let no of oxygen atoms be y

charge on one oxygen atom is 2

2y = 11x

so, y=11x/2

hence compound is AxA3x[O11X/2]

i.e A4x[O11x/2]

i.eA8x[O11x]

i.eA8O11 

it's wrong....