if an element shows two oxidation states +2 and +3 and form oxide in such a way that ratio of the element showing +2 and +3 state is 1:3 in compound. formula of compound is....????

(please tell me how to solve it)

Question

if an element shows two oxidation states +2 and +3 and form oxide in such a way that ratio of the element showing +2 and +3 state is 1:3 in compound. formula of compound is....????

(please tell me how to solve it)

Jaya IITK · Answer

let no. of atoms in +2 oxidation state be x then in +3 is 3x thus charge on oxygen has to be 2x+9x=11x thus formula is MxM9xO11x ans: M10 O11 Pls approve my answer by clicking on yes below!!!!!!!!!

Abhijat Pandey · Answer

Sir. thank you... But the answer is M8O11... how is this done...???

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if an element shows two oxidation states +2 and +3 and form oxide in such a way that ratio of the element showing +2 and +3 state is 1:3 in compound. formula of compound is....???? (please tell me how to solve it)

if an element shows two oxidation states +2 and +3 and form oxide in such a way that ratio of the element showing +2 and +3 state is 1:3 in compound. formula of compound is....????

(please tell me how to solve it)

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if an element shows two oxidation states +2 and +3 and form oxide in such a way that ratio of the element showing +2 and +3 state is 1:3 in compound. formula of compound is....???? (please tell me how to solve it)

if an element shows two oxidation states +2 and +3 and form oxide in such a way that ratio of the element showing +2 and +3 state is 1:3 in compound. formula of compound is....???? (please tell me how to solve it)

2 Answers

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if an element shows two oxidation states +2 and +3 and form oxide in such a way that ratio of the element showing +2 and +3 state is 1:3 in compound. formula of compound is....????

(please tell me how to solve it)