if an element shows two oxidation states +2 and +3 and form oxide in such a way that ratio of the element showing +2 and +3 state is 1:3 in compound. formula of compound is....????(please tell me how to solve it)

let no. of atoms in +2 oxidation state be x

then in +3 is 3x

thus charge on oxygen has to be 2x+9x=11x

thus formula is MxM9xO11x

ans: M10 O11

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Sir. thank you... But the answer is M8O11... how is this done...???