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if the frequency of an element is 400Hz and a=b=1,then find the element using mosley equation
Dear apoorv mishra,
Mosely's Equation is √v = a(Z-b)
Here v is the frequency, a and b are constants !!
Now according to the given information here a=b=1 & v=400 Hz so substituting th values in the equation abouve we get,
√400 = 1(Z-1)
20 = Z-1
Therefore Z = 21 which is Scandium !!
The answer therefore is Scandium .
Hope this helped you ..!!
If you loved the answer then please do not forget to approve it by clicking on "Yes" below..!!!
√v=a(z-b)
Therefore z=21 it is scandium
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