How do you calculate the n factor of a substance in acidic or basic media? For eg. What is the n factor of K2Cr2O7 in acidic medium?

Question

Jaya IITK · Answer

for acids its replaceable H+ ion( That is H+ directly attached to O), for basic its OH- ion

for salts total +ve or total -ve charge

for redox reaction it is no. of e- exchanged per mole of the cmpd of whose n factor has to be found

see for Mn and remember any form of Mn changes to Mn2+ in acidic and Cr to Cr3+

K2Cr2O7 -> Cr3+

THUS OXDATION STATE CHANGES FROM +6 TO +3

thus n factor= +6

sanchit agrawal · Answer

Thanks for the answer. I still need to know how you get Mn2+ and Cr3+ in acidic medium. Also how would you know the charge of ions for different elements in different media? For e.g. Charge of Cu ion in basic media?

Rithik Jain · Answer

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Ankit Pradhan · Answer

For acids--Its replaceable H+ ion( That is H+ directly attached to O) For basic--Its OH- ion For salts--total +ve or total -ve charge For redox reaction--It is no. of e- exchanged per mole of the compound of whose n factor has to be found.

Rishi Sharma · Answer

Dear Student,
Please find below the solution to your problem.

for acids its replaceable H+ ion( That is H+ directly attached to O), for basic its OH- ion
for salts total +ve or total -ve charge
for redox reaction it is no. of e- exchanged per mole of the cmpd of whose n factor has to be found
see for Mn and remember any form of Mn changes to Mn2+ in acidic and Cr to Cr3+
K2Cr2O7 -> Cr3+
THUS OXDATION STATE CHANGES FROM +6 TO +3
thus n factor= +6

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How do you calculate the n factor of a substance in acidic or basic media? For eg. What is the n factor of K2Cr2O7 in acidic medium?

How do you calculate the n factor of a substance in acidic or basic media? For eg. What is the n factor of K2Cr2O7 in acidic medium?

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