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for [Co(NH3)6]^(+3) in many books hybridisation is given as d2sp3. this is correct. but for compound [Fe(NH3)6]^(+2) the hybridisation is given as sp3d2. WHY? Both Co3+ and Fe 2+ are d^6 confguration. and nh3 is strong field ligand. so it should also form inner spin complex in fe2+ compound. PLEASE HELP. I WILL BE VERY GRATEFUL OF YOU.....


for [Co(NH3)6]^(+3) in many books hybridisation is given as d2sp3. this is correct.


 but for compound [Fe(NH3)6]^(+2) the hybridisation is given as sp3d2. WHY?  


Both Co3+ and Fe 2+ are d^6 confguration. and nh3 is strong field ligand. so it should also form inner spin complex in fe2+ compound.


PLEASE HELP. I WILL BE VERY GRATEFUL OF YOU.....


Grade:

1 Answers

vijesh jayan
49 Points
10 years ago

r u sure that the book is correct

it shld be +3 instead of +2 in [Fe(NH3)6]^+2

acc to me the one with oxidation number 2 will have co ordination number 4

and the one with 3 oxidaton number will have co ordination number 6

so fe with oxidation number 2 will not exhibit [Fe(NH3)6]^+2 as the co ordination number here is 6

so the possibile formula is [Fe(NH3)4]^+2 OR [Fe(NH3)6]^+3

so if u are taking [Fe(NH3)6]^+3 ------- config is -------- 3d6 , 4s2

now remove 3 e

then u will get ------------ 3d5 -------- will not pair up --------------- so u will get sp3d2 ---- dezired answer

is what i think

they must by mistake printed +2 instead of +3

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