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E = 13.6(1/n2 - 1/x2)
E is energy os photon emmited when electron falls from higher state x to lower state n...
E = 0.6537ev (given)
so , 0.6537 = 13.6(1/n2-1/x2)
(3/4) (0.85)/13.6 = [ 1/n2 - 1/x2 ]
(3/4)/16 = 3/64 = [ 1/n2 - 1/x2 ]
now , here we can use hit & trial method , for n = 4 & x = 8 this relation is satisfied
[1/16 - 1/64] = [ 1/n2 - 1/x2 ]
n = 4 , x = 8
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