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an oleum sample is labelled as (100+x)% and it contain 80/3 % free sulphur dioxide by weight.... x=?
Dear student,
Use stoichiometry concept...
Oleums can be described by the formula ySO3.H2O where y is the total molar sulfur trioxide content. The value of y can be varied, to include different oleums. They can also be described by the formula H2SO4.xSO3 where x is now defined as the molar free sulfur trioxide content. Oleum is generally assayed according to the free SO3 content by weight
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