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calculate the percentage of p-charater in the orbitals of P4 forming p-p bond
Dear student, Hybridization of P4 is sp3.which means one s-orbital and 3 p-orbitals.% p = (p-orbitals / total orbitals)x100%p = (3/4)x100 = 75 % Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi
Dear student,
Hybridization of P4 is sp3.which means one s-orbital and 3 p-orbitals.% p = (p-orbitals / total orbitals)x100%p = (3/4)x100 = 75 %
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
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Askiitians Expert
Sagar Singh
B.Tech, IIT Delhi
P is SP3 hybridised in P4 so P character is 75%
in p4 phosphorus is p3 hybridised s orbotal do not participate on bonding lone pair electrons are prsent in pure s orbital thus 100% p charecterin p4 molecule s orbital do not participate in bonding so molecule is p3 hybridised so p char. 100%
There is no sp3 hybridisation in p4Bcoz there is participate pure p orbital in hybridisation Sooo there is 100% pure p orbital
In P4 molecule there are all single bonds which means that P4 has sp3 hybridization. Hence % p character = 3/4*100 = 75% which is the required answer.
Their is no hybridization in P4 due to Drago's rule ( en of p is 2.12 and p is of 3rd period) and it's lone pair is in inactive s orbital just like PH3
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