Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
explain e- charge transfer in details in context with kmno4 explain e- charge transfer in details in context with kmno4
explain e- charge transfer in details in context with kmno4
Dear student, Mn in the tetrahredral [MnO4]– anion is Mn(VII), so formally d(0), with no valence electrons. The bonding can be described as primarily ionic, so we can think of the filled orbitals as simply the electrons on the [O]2- groups surrounding the Mn - the highest energy filled orbitals will be the O 2p atomic orbitals. Crystal field theory predicts a splitting of the empty d orbitals on Mn into two energy levels, the lower two "e" orbitals and the upper three "t2" orbitals. There are two transitions in the UV-vis spectrum of the [MnO4]– anion: one from the filled O 2p to the lower-energy "e" Mn d orbitals, and one from the filled O 2p to the higher-energy "t2" Mn d orbitals. Both are ligand-to-metal charge transfer bands, because they formally move electrons from the O to the Mn, which is why the colour is so intense -- CT bands have extremely high extinction coefficients. Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi
Dear student,
Mn in the tetrahredral [MnO4]– anion is Mn(VII), so formally d(0), with no valence electrons. The bonding can be described as primarily ionic, so we can think of the filled orbitals as simply the electrons on the [O]2- groups surrounding the Mn - the highest energy filled orbitals will be the O 2p atomic orbitals. Crystal field theory predicts a splitting of the empty d orbitals on Mn into two energy levels, the lower two "e" orbitals and the upper three "t2" orbitals. There are two transitions in the UV-vis spectrum of the [MnO4]– anion: one from the filled O 2p to the lower-energy "e" Mn d orbitals, and one from the filled O 2p to the higher-energy "t2" Mn d orbitals. Both are ligand-to-metal charge transfer bands, because they formally move electrons from the O to the Mn, which is why the colour is so intense -- CT bands have extremely high extinction coefficients.
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
Askiitians Expert
Sagar Singh
B.Tech, IIT Delhi
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -