Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
calculate de-Broglie wavelength of an electron travelling at 1% of the speed of light.
a) 2.73 x 10-24
b) 2.42 x 10-10
c) 242.2 x 1010
d) none of these
plz solve and explain the solution.....
λ = h/mc
In your problem, velocity = c/100 ( since the velocity is 1 %)
Sub c=c/100 in above equation, You will get λ = 100 h/mc
Sub values of h,m and c. Arrange the powers of 10. The answer will be 2.42 x 10-10.
So, Your answer will be (b) 2042 x 10-10. Hope you understand. Do well.
(lamda) = h/mv (h is planks constant , h = 6.6*10-34 & m is mass of particle)
v = 1% of speed of light = C/100 (C is speed of light & C=3*108)
lamda = h/mv
=100h/mC (m = 9.1*10-31kg , mass of electron)
= 0.241*10-9 m
=0.241nm or 2.41(angstorm)
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !