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calculate de-Broglie wavelength of an electron travelling at 1% of the speed of light. a) 2.73 x 10 -24 b) 2.42 x 10 -10 c) 242.2 x 10 10 d) none of these plz solve and explain the solution.....
λ = h/mc In your problem, velocity = c/100 ( since the velocity is 1 %) Sub c=c/100 in above equation, You will get λ = 100 h/mc Sub values of h,m and c. Arrange the powers of 10. The answer will be 2.42 x 10-10. So, Your answer will be (b) 2042 x 10-10. Hope you understand. Do well.
λ = h/mc
In your problem, velocity = c/100 ( since the velocity is 1 %)
Sub c=c/100 in above equation, You will get λ = 100 h/mc
Sub values of h,m and c. Arrange the powers of 10. The answer will be 2.42 x 10-10.
So, Your answer will be (b) 2042 x 10-10. Hope you understand. Do well.
(lamda) = h/mv (h is planks constant , h = 6.6*10-34 & m is mass of particle) v = 1% of speed of light = C/100 (C is speed of light & C=3*108) lamda = h/mv =100h/mC (m = 9.1*10-31kg , mass of electron) = 0.241*10-9 m =0.241nm or 2.41(angstorm)
(lamda) = h/mv (h is planks constant , h = 6.6*10-34 & m is mass of particle)
v = 1% of speed of light = C/100 (C is speed of light & C=3*108)
lamda = h/mv
=100h/mC (m = 9.1*10-31kg , mass of electron)
= 0.241*10-9 m
=0.241nm or 2.41(angstorm)
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