SAGAR SINGH - IIT DELHI
Last Activity: 14 Years ago
Dear student,
For a many electron atom EPE = -<Ze2/r >
Here the brackets represent an average -- we must take an average because the electron does not remain at one fixed value of r .
Earlier, we noted that Eorb = -Ze2/2 <1/r> These averages are dominated by contributions at SMALL r. When r is SMALL,
(1/r) is LARGE; thus, the larger the fraction of its time an electron spends at SMALL r, the MORE NEGATIVE -Ze2/2 <1/r> will be,and the ELECTRON will be "BOUND" MORE TIGHTLY to the nucleus (i.e Eorb will be more NEGATIVE).
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
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Sagar Singh
B.Tech, IIT Delhi