Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
What is the amount of potassium acetate to be added to 1 litre of N/10 acetic acid to make a buffer solution of pH=4 using acetic acid and potassium acetate? The dissociation constant of acetic acid =2*10^-5
let the amount of potassium acetate = m grams M(CH3COOK) = m/92 .........1 normality of acetic acid = molarity*1 M( CH3COOH) = 0.1 Ka = [salt][H+]/[acid] PH =4 means [H+] = 10-4 Ka = M(CH3COOK][H+]/[CH3COOH] 2*10-5 = [m/92][10-4]/[10-1] m= 1.84grams
let the amount of potassium acetate = m grams
M(CH3COOK) = m/92 .........1
normality of acetic acid = molarity*1
M( CH3COOH) = 0.1
Ka = [salt][H+]/[acid]
PH =4 means [H+] = 10-4
Ka = M(CH3COOK][H+]/[CH3COOH]
2*10-5 = [m/92][10-4]/[10-1]
m= 1.84grams
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -