If the weight of 5.6 lit of of a gas is 11g at stp.The gas is

1. SO2

2. NO

3. N2O

Dear Amit

wt of 22.4 lit gas=(22.4/5.6)*11=44g

wt of N₂O = 14*2+16=44g

All the best.

AKASH GOYAL

AskiitiansExpert-IITD

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22.4L of gas = 1mol

1L= 1/22.4 mol

5.6L = 1/4 mol

let molar mass of gas is M then

5.6L = M/4gm =11gm  (given)

    so M=11*4=44gm

so the gas is N₂O