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If the weight of 5.6 lit of of a gas is 11g at stp.The gas is 1. SO2 2. NO 3. N2O

If the weight of 5.6 lit of of a gas is 11g at stp.The gas is


1. SO2


2. NO


3. N2O

Grade:10

2 Answers

AKASH GOYAL AskiitiansExpert-IITD
419 Points
10 years ago

Dear Amit

wt of 22.4 lit gas=(22.4/5.6)*11=44g

wt of N2O = 14*2+16=44g

All the best.

AKASH GOYAL

AskiitiansExpert-IITD

 

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vikas askiitian expert
509 Points
10 years ago

22.4L of gas = 1mol

1L= 1/22.4 mol

5.6L = 1/4 mol

let molar mass of gas is M then

5.6L = M/4gm =11gm  (given)

    so M=11*4=44gm

so the gas is N2O

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