Grade 10Inorganic Chemistry
Gas
If the weight of 5.6 lit of of a gas is 11g at stp.The gas is
1. SO2
2. NO
3. N2O
2 Answers
Dear Amit
wt of 22.4 lit gas=(22.4/5.6)*11=44g
wt of N2O = 14*2+16=44g
All the best.
AKASH GOYAL
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22.4L of gas = 1mol
1L= 1/22.4 mol
5.6L = 1/4 mol
let molar mass of gas is M then
5.6L = M/4gm =11gm (given)
so M=11*4=44gm
so the gas is N2O
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