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If the pH of a mixture of 10 ml of 0.1 M NH4OH and 10 ml of NH4Cl solution is 8, the pKb value of NH4OH is then closest to
a)3 b)5 c)7 d)9
in aqueous solution
NH4OH ----> NH4+ + OH-
NH4Cl ---------> NH4+ + cl-
Kb for NH4OH = [NH4+][OH-] /NH4OH
here common ion effect is observed ....
Kb = [NH4Cl][OH-]/NH4OH
=[OH-] (NH4Cl =NH4OH)
H+ = 10-8 (given)
OH- =Kw/H+ =10-6
Kb = 10-6
Pkb =6
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