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Find out the value of electrostatic potential energy of 2 electrons separated by 3.0 angstrom in vacuum.

Find out the value of electrostatic potential energy of 2 electrons separated by
3.0 angstrom in vacuum.

Grade:11

1 Answers

ABHISHEK JAIN AskiitiansExpert-IITD
20 Points
11 years ago

Dear Shambhavi,

 

since P.E. = Kq1q2\r

charge on electron = 1.6 × 10^ -19

distance b/w two electrons = 3Å = 3 × 10^ -10 meter

coulamb's constant k = 9 × 10^9

put the values in above formula:

P.E. = 9 × 10^9 × 1.6 × 10^-19 × 1.6× 10^-19 ÷ 3 × 10^-10

      = 7.676 × 10^-19 J


 

 

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