suryakanth AskiitiansExpert-IITB
Last Activity: 14 Years ago
Dear Raj,
B2H6 is the answer,
The monomer BH3 is unstable since the boron atom is only surrounded by six valence electrons, and thus, to form a stable octet, shares electrons with a B-H bond on another boron atom, forming a B-H-B 3-center-2-electron bond. In diborane, there are two such bonds: two H atoms bridge the two B atoms, leaving two additional H atoms in ordinary B-H bonds on each B.
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Suryakanth –IITB