Why square root is taken for polarisation energy in Pauling's electronegativity expression?D = EA-B – ((EA-A) (EB-B)) 1/2(XA – XB) = (D) 1/2; if D is measured in eV /molecule

you ask deep questions srinivas.

But as it occurs I don't know the asnwer to this question.

I can find it out for you ofcourse but there would be methods involved in the development of theory which are out of your rnage.

please accept it for a fact for the time being.

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