Why square root is taken for polarisation energy in Pauling's electronegativity expression?

D = E_A-B – ((E_A-A) (E_B-B)) ^1/2

(X_A – X_B) = (D) ^1/2; if D is measured in eV /molecule

you ask deep questions srinivas.

But as it occurs I don't know the asnwer to this question.

I can find it out for you ofcourse but there would be methods involved in the development of theory which are out of your rnage.

please accept it for a fact for the time being.

Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.

DO APPROVE IF THE ANSWER HELPS YOU.

Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Regards,

Askiitians Experts

Rahul- IIT Roorkee