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Why square root is taken for polarisation energy in Pauling's electronegativity expression? D = E A-B – ((E A-A ) (E B-B )) 1/2 (X A – X B ) = (D) 1/2 ; if D is measured in eV /molecule

Why square root is taken for polarisation energy in Pauling's electronegativity expression?


D = EA-B – ((EA-A) (EB-B)) 1/2


(XA – XB) = (D) 1/2; if D is measured in eV /molecule

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1 Answers

Rahul askIITiansExpert.IITR
110 Points
10 years ago
you ask deep questions srinivas.

But as it occurs I don't know the asnwer to this question.

I can find it out for you ofcourse but there would be methods involved in the development of theory which are out of your rnage.

please accept it for a fact for the time being.

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