FITJEE
Last Activity: 12 Years ago
The total number of moles of a solute, regardless of state, in one liter of solution. Given as moles/L.
Calculate the equilibrium molarities of H2, I2, and HI
H2(g) + I2(g) <--> 2 HI(g)
Initial..................... 0.05.... 0.06 ...........0
Change...................- x ......- x..............+x
Equilibrium.......... 0.05 - x.. 0.06-x...........x
Equilibrium constant, Kc = [HI]2 / [H2] [I2] = 58.6
......................................… = [x]2 / [0.05-x] [0.06-x] = 58.6
Solve for x to get the change in the number of moles, and subsequently the number of moles of each compound in equilibrium
Molarity of H2 = [0.05-x] / 1.00L
Molarity of I2 = [0.06-x] / 1.00L
Molarity of HI = x / 1.00L (2)
Equivalent weight is the atomic weight of an element or radical divided by the valence it assumes in a chemical compound.