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2 substance a(t1/2 =5 min ) and b t1/2=15 min follow 1 st order kinetics are taken in such a way that initially [a]=4[b] .calculate time after which the conc. of both substance will be equal.

2 substance a(t1/2 =5 min ) and b t1/2=15 min follow 1st order kinetics are taken in such a way that initially [a]=4[b] .calculate time after which the conc. of both substance will be equal.

Grade:12

1 Answers

Neeti
571 Points
6 years ago
apply the formula t = 2.303/ k (log a0/a) find k using t½ and then put their values keeping final concentration equal. :)

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