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Grade 11Inorganic Chemistry

2 moles of N2H4 loses 20 moles of electrons to form a new compond Y. assuming that all nitrogen appears in the new compound , what is the oxidation state of nitrogen in Y ? [there is no change in the oxidation state of hydrogen.]

Profile image of Shadic The Hedgehog
6 Years agoGrade 11
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2 Answers

Profile image of Arun
6 Years ago
 
1 mole N2H4 loses 10mole e- 
So, 1 N2H4 loses 10e- 
So,  new compound Y=(N2H4)10+ 
Charge on y is 10+
Let charge on N be x. 
2x+4=10
x=+3
 
Profile image of Vikas TU
6 Years ago
Dear student 
2 Nole of N2H4 Loses 20 electron 
So, 1 mole Loses 10 mole electron
Oxidation state of NItrogen in n2h4 is -2.  2(-2) + 4(+1)= 0
therefore two N makes it -4 , since they lose 10 e-  , hence total charge is +6, and since H is still +1 ,  Two N divides the +6 .
then ox state of N is +3

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