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Grade: 11
        2 mole of an ideal gas is heated at constant pressure of 1 ATM from 27 degree Celsius to 127 degree Celsius if cv=20+10^-2 T Jk^-1 mol^-1 then q and delta U for the process are
2 years ago

Answers : (1)

Ajpa mishra
15 Points
							
dU=nCv∫dT=∫2× [20+10^-2T] dT
=40∫dT + 2×10^-2 ∫TdT
(lower limit 300K upper limit 400K)
40(400-300)+ 2×10^-2 {(1600/2) - (900/2)}
=4000+700
=4700 J ans 1
Further q=4700+nRdT
                 4700+1662.8 J 2nd part ans.
                4700+2×8.314(400-300)
 
one year ago
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