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18 m solution of sulphuric acid was diluted to 1000 l. Find the normality of solution.

18 m solution of sulphuric acid was diluted to 1000 l. Find the normality of solution.

Grade:12th pass

1 Answers

Arun
25750 Points
5 years ago
Change in molarity after dilution =
M1V1 = M2V2
18 M x 1L = M2 x 1000 L
M2 = 18M x 1L/1000 L
     = 0.018 M

Now,
Normality = n x Molarity
n- no. of replaceble ion i.e 2 ( H2SO4 produce two H+ ions )
N = 2 x 0.018  = 0.036 N

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