14.70gm of dibasic acid was dissolved in 250 ml.25ml of this solution was neutralised by 30 ml of 1 M NaOH solution. The molecular weight and equivalent weight of the acid respectively are

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Shifa · Answer

Equate the gram equivalent of dibasic acid (n-factor :2) to the given 30 ml of naoh sol i.e N × V ( OF ACID) = M× nf × v ( of NaOH).... Use formula of N that has molecular mass as unknown aand then find eq.wt ANS : 98 & 49

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14.70gm of dibasic acid was dissolved in 250 ml.25ml of this solution was neutralised by 30 ml of 1 M NaOH solution. The molecular weight and equivalent weight of the acid respectively are

14.70gm of dibasic acid was dissolved in 250 ml.25ml of this solution was neutralised by 30 ml of 1 M NaOH solution. The molecular weight and equivalent weight of the acid respectively are

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14.70gm of dibasic acid was dissolved in 250 ml.25ml of this solution was neutralised by 30 ml of 1 M NaOH solution. The molecular weight and equivalent weight of the acid respectively are

14.70gm of dibasic acid was dissolved in 250 ml.25ml of this solution was neutralised by 30 ml of 1 M NaOH solution. The molecular weight and equivalent weight of the acid respectively are

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