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Grade: 12th pass

                        

10 grams of metal oxide contains 6 grams of Oxygen.the equivalent weight of the metal carbonate is

3 years ago

Answers : (1)

Vikas TU
12277 Points
							
let Metal oxide be M2Ox .
then Total moles of compound = 10/(2M + 16x)
moles of M = > 20/(2M+16x) = 4/2M
moles of O => 10x/(2M + 16x) = 6/16x
solving both eqns . we get,
M = 5.09. and x= 1 approx.
Hence eq. weight for metal carbonate => M2CO3
=> 2M + 48 + 12
=> 10.18 +  48 + 12
=> 70.18.
3 years ago
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