Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

1.In a closed vessel,4 moles of hydrogen & 3 moles of iodine were heated at 450K . At equilibrium, 5 moles of HI were formed.Calculate, the value of Kc. 2.Calculate the equilibrium constant , for the reaction, if one mole of phosphorous pentachloride is heated in a closed vessel of volume 10metercube. At the equilibrium , 0.40 mole of phosphorous trichloride , was found to be present.

1.In a closed vessel,4 moles of hydrogen & 3 moles of iodine were heated at 450K . At
equilibrium, 5 moles of HI were formed.Calculate, the value of Kc.
2.Calculate the equilibrium constant , for the reaction, if one mole of phosphorous pentachloride is heated in a closed vessel of volume 10metercube. At the equilibrium , 0.40
mole of phosphorous trichloride , was found to be present.

Grade:11

1 Answers

Kamlesh Kumar
askIITians Faculty 60 Points
7 years ago
H2 + I2 ============= 2 HI
initialiy 4mole 3 mole 0 moles
at equlibrium (4_ x) mole (3_ x)mole 5 mole(2 x mole )

2 x =5
5
x =____ = 2.5
2
[HI]2 [ 2.5 ]2 6.25
kc=______________=_______________ = ____________= 1
[H2 ] x [I2] [2.5] x [2.5 ] 6.25


So value of Kc= 1


PCl5==============PCl3 + Cl2
1 mole 0 mole 0 mole
(1__ x) mole x mole x mole
given at equilibrium x = 0.40
so at equilibrium moles of PCl5=1_x =1_0.4 = 0.6

moles of PCl3= 0.4
moles of Cl2 =0.4

( 0.4/ 10) X (0.4/10) 0.16 X 10
KC=____________________ =__________________ =0.026
( 0.6/10) 100 X 0.60

THANKS&REGARDS
kamlesh kumar
askiitians faculty


Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free