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```
a line x=k intersects graph of y=log 5 x and the graph of y=log 5 (x+4) .the distance b/w points of intersection is 0.5 , given k=a+(b) 1/2. .where a & b are integers..the value of a+b is...........
a line x=k intersects graph of y=log5x and the graph of  y=log5(x+4) .the distance b/w points of intersection is    0.5      , given k=a+(b)1/2..where a & b are integers..the value of    a+b  is...........

```
11 years ago

147 Points
```							Dear rahul
given distance b/w points of intersection is    0.5
ie  log5(k+4) -log5(k)  =1/2
or log5(k+4)/k  =1/2
or (k+4)/k  =√5
k=4/(√5 -1)
=√5 +1
so  a=1   and b=5
a+b=6
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```
11 years ago
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