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a line x=k intersects graph of y=log5x and the graph of  y=log5(x+4) .the distance b/w points of intersection is    0.5      , given k=a+(b)1/2..where a & b are integers..the value of    a+b  is...........

10 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
							

Dear rahul

given distance b/w points of intersection is    0.5 

ie  log5(k+4) -log5(k)  =1/2

or log5(k+4)/k  =1/2

or (k+4)/k  =√5

  k=4/(√5 -1)

    =√5 +1

 so  a=1   and b=5

a+b=6

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Badiuddin

10 years ago
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