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a line x=k intersects graph of y=log5x and the graph of y=log5(x+4) .the distance b/w points of intersection is 0.5 , given k=a+(b)1/2..where a & b are integers..the value of a+b is...........
Dear rahul given distance b/w points of intersection is 0.5 ie log5(k+4) -log5(k) =1/2 or log5(k+4)/k =1/2 or (k+4)/k =√5 k=4/(√5 -1) =√5 +1 so a=1 and b=5 a+b=6 Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
Dear rahul
given distance b/w points of intersection is 0.5
ie log5(k+4) -log5(k) =1/2
or log5(k+4)/k =1/2
or (k+4)/k =√5
k=4/(√5 -1)
=√5 +1
so a=1 and b=5
a+b=6
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation.
All the best. Regards,Askiitians ExpertsBadiuddin
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