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Grade: 11

                        

[ x-1 ] + [ x-5 ] = 20

6 years ago

Answers : (3)

Shrey
49 Points
							x-1+x-5=20
2x-6=20
2x=20+6
2x=26
x=26/2
x=13
Please approve my answer by clicking approved if you liked it.
						
6 years ago
shivam chopra
18 Points
							[ x-1 ] + [ x-5 ] = 20 . " [ x-1 ].. " these brackets are of greatest integer function!! if it was that much simpler then why should i`ve asked it , for querry see chapter functions of class 12th
						
6 years ago
vaanya
18 Points
							if u equate each bracket to 0 then u get x=1,5 which would give you 3 cases: x>=5  ,   1<=x<5    , x<=1
(u can try it out by putting a value or u can remember this as a rule...when the case gives a positive value inside bracket you can simply take out the integer with the sign without worrying abt GIF...but if the case gives a negative value inside GIF bracket then u take out the integer from the bracket with the sign AND ALSO subtract 1 for the bracket)
Case 1: x>=5, (this gives positive values for both brackets)
[x-1]+[x-5]=20
[x]-1+[x]-5=20
[x]=13
x belongs to [13,14)

Case 2: 1<=x<5 (this gives a positive value for the 1t bracket and a negative value for the second bracket)
[x-1]+[x-5]=20
[x]-1+[x]-5`-1`=20 (note the part in apostrophes)
[x]=27/2 which is not an integer and GIF can never be a non-integer so this case gives us no value.

Case 3: x<1 (this gives both brackets as negative)

[x-1]+[x-5]=20
[x]-1`-1`+[x]-5`-1`=20
[x]=14
x belongs to [14,15)

so the complete answer is [13,15)

i hope u got what i am trying to say. approve if u understood and liked the answer.
						
6 years ago
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