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Why sin(-π) ,sinπ ,sin2πis equal to 0..... please explain how?

Why sin(-π) ,sinπ ,sin2πis equal to 0..... please explain how?

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
5 years ago
Sin (x) in a right angle triangle is defined as the ratio of opposite side on the hypotenuse

So if you try and draw one such triangle you end up having oppositeheight as 0 so

sin(x) = 0/ hypotenuse = 0

hope it settles

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