Samyak Jain
Last Activity: 5 Years ago
Let the point on the ground right under the centre of the circle be origin (0,0).
Consider verticle line through the origin to be y-axis, horizontal axis be x-axis and then z-axis is perpendicular
to both x and y axes passing through (0,0).
The velocity vector is in a plane parallel to x-z plane. Now, imagine an instance of the motion of the particle.
Join the origin to the point of the particle. This is the radius vector, which is in the x-y plane, perpendicular to x-z plane (i.e. perpendicular to the plane parallel to x-z plane where horizontal table is present).