Grade 11IIT JEE Entrance Exam
what will be the angular velocity about the origin...
1 Answer
Arun
Particle starts from (0m , 8m) from rest with uniform velocity of 3 m/s in the x-direction so after 5 seconds the distance a particle will traverse along the x-axis is 3*5= 15m
so new position of the particle is (15m , 8m).
So the distance of this new position to the origin is
\square-root(15- 0)2 + (8 - 0)2
= 17
Angular velocity about origin is given by
W = v/r
= 3/17 rad/sec
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