What is the usual JEE Main cutoff for getting into

Question

What is the usual JEE Main cutoff for getting into IIST Thiruvananthapuram?

Arun Kumar · Accepted Answer

Hi Aneesh,A. General Candidates (GEN): At least 20% marks in aggregate and at least 5% marks in each of the three subjects (Physics Chemistry and Mathematics).B. Other Backward Community – Non Creamy Layer OBC (NCL) Candidates: At least 18% marks in aggregate and at least 4.5% marks in each of the three subjects (Physics Chemistry and Mathematics).C. SC, ST & PD Candidates: At least 10% marks in aggregate and at least 2.5% marks in each of the three subjects (Physics Chemistry and Mathematics).Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty

IIT JEE Entrance Exam> What is the usual JEE Main cutoff for get...

What is the usual JEE Main cutoff for getting into IIST Thiruvananthapuram?

Aneesh , 11 Years ago

Arun Kumar

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Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-

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Sum of series 2[n/2] ! [n/2]!/ n! [2Co-2C2+3C2....+[-1]^n[n+1]2Cn] where n is an even positive integer. Kindly provide solution of this question and how to generalise this. How do we know that which expansion will give this?

iit jee entrance exam

IIT JEE Entrance Exam> What is the usual JEE Main cutoff for get...

What is the usual JEE Main cutoff for getting into IIST Thiruvananthapuram?

Aneesh , 11 Years ago

Arun Kumar

LIVE ONLINE CLASSES

Other Related Questions on iit jee entrance exam

Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-

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Sum of series 2[n/2] ! [n/2]!/ n! [2Co-2C2+3C2....+[-1]^n[n+1]2Cn] where n is an even positive integer. Kindly provide solution of this question and how to generalise this. How do we know that which expansion will give this?

iit jee entrance exam