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What is the range of the function (sinx)*(arcsinx)? Answer:[0, π/2sin1]

What is the range of the function
(sinx)*(arcsinx)?
Answer:[0, π/2sin1]

Grade:12th pass

1 Answers

Vikas TU
14149 Points
4 years ago
Hiii Rustic 
The range of arcsinx is : [--π/2 , π/2]
From the definition of arcsinx . which is also defined as sin-1x  if sinx = u 
arcsinx = u =x 
i.e arcsinx (sinx) = x 
as domain and range of x is (-inf. , inf ) 
domain and rnge of arcsinx(sinx) =   (-inf. , inf )
 

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