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`        What is the range of the function(sinx)*(arcsinx)?Answer:[0, π/2sin1]`
5 months ago

Vikas TU
9468 Points
```							Hiii Rustic The range of arcsinx is : [--π/2 , π/2]From the definition of arcsinx . which is also defined as sin-1x  if sinx = u arcsinx = u =x i.e arcsinx (sinx) = x as domain and range of x is (-inf. , inf ) domain and rnge of arcsinx(sinx) =   (-inf. , inf )
```
5 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions