what is the magnitude of electric intensity due to a dipole of movement 2 × 10-8 coulomb meter at a point distance 1 m from the centre of dipole when line joining the point to the centre of the pole makes an angle of 60° with dipole axis ?

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Arun · Answer

V=Kpcosθ/r^2 => 9×10^9 × 2×10^-8 × cos60° / (3)^2 =10V Hope you understand In case of any difficulty, please feel free to ask again. Thanks and regards Arun

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what is the magnitude of electric intensity due to a dipole of movement 2 × 10-8 coulomb meter at a point distance 1 m from the centre of dipole when line joining the point to the centre of the pole makes an angle of 60° with dipole axis ?

what is the magnitude of electric intensity due to a dipole of movement 2 × 10-8 coulomb meter at a point distance 1 m from the centre of dipole when line joining the point to the centre of the pole makes an angle of 60° with dipole axis ?

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what is the magnitude of electric intensity due to a dipole of movement 2 × 10-8 coulomb meter at a point distance 1 m from the centre of dipole when line joining the point to the centre of the pole makes an angle of 60° with dipole axis ?

what is the magnitude of electric intensity due to a dipole of movement 2 × 10-8 coulomb meter at a point distance 1 m from the centre of dipole when line joining the point to the centre of the pole makes an angle of 60° with dipole axis ?

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