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`        Two particles initially seperated by 72 m having initial velocities 1m/s and 2m/s respectively and accelerations 1m/s^2 and 2m/s^2 respectively are moving towards each other. Find the time taken to meet. `
one year ago

763 Points
```							Dear Dinesh,let after t second they will meet each other . then sum of distances covered by both in t second will be equal to 72mNow, distance covered by 1st particle , s = 1.t +1/2 .1.t2distance covered by 2nd particle, S= 2.t +1/2.2.t2sum of distances =72 = t+2t+1/2t2+t2 after simply we get (t-6)(t+8) = 0 => t = 6 second hence, after 6 second they will meet each other.
```
one year ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions